National Testing Agency (NTA) has announced the results of the country’s biggest engineering entrance exam JEE-Main-2020 September exam on Friday at 11 pm. Only state toppers and 100 percentile were released by NTA.
Brijesh Maheshwari, Director of the Allen Career Institute, said that according to the information received from various media sources, a list of 55 topper students from all the states was released. A total of 24 candidates have scored 100 percentile. It consists of 4 toppers from Rajasthan, viz. Akhil Agarwal, Akhil Jain, Parth Dwivedi and R Muhender Raj. All four are Classroom Students of ALLEN Career Institute. Apart from this, a list of State Wise Female Student Toppers was also released, which included 38 girls.
It is noteworthy that All India Rank is also to be released jointly on the basis of the results of JEE-Mains January and September examinations, out of which 2.5 lakh students will be appeared in JEE-Advanced. The exam will be held on September 27, whose registration starts from September 12. Its schedule has been released by JOSA. Thus, All India Rank can also be released soon.
The examination was conducted from September 1 to 6 for which around 8.58 lakh candidates had registered out of which nearly 6.3 lakh appeared.
In JEE-Main September, 8 lakh 58 thousand 273 students were registered this year. This online exam was conducted in 12 shifts.
How All India Rank will be determined?
Students who appeared in both January and September examinations, their best of the two NTA scores would be considered for the preparation of ALL India Ranks.
In case two or more candidates secure equal percentile scores in JEE Main 2020 result, then the candidate who secures more percentile score in Mathematics would be ranked higher followed by the candidate who secures more percentile score in Physics would be ranked higher. If both these scores are also the same, the NTA score of chemistry will be taken into consideration.
In case the NTA scores of the three subjects remain the same, then the candidate who is older will be given higher rank. Along with this, the eligibility cutoff for appearing in JEE Advanced on the basis of JEE Main September result will be released as 7 decimal places NTA score. On the basis of JEE-Main Result 2020, the top 2.5 lakh students comprising all categories will be eligible to give JEE-Advanced, which includes 1, 01,250 of general category, 25000 of general EWS, 67500 of OBC, 37500 of SC and 18750 of ST.
